Question

1. A pair of dice are tossed. What is the probability of getting a total of:
a. 5;
b. At most 4

Answer 1

Answer on Question #62273 – Math – Statistics and Probability

Question

1. A pair of dice is tossed. What is the probability of getting a total of:

a. 5;

b. At most 4

Solution

When two dice are thrown simultaneously, thus number of events can be $6^2 = 36$ because each die has 1 to 6 number on its faces. Then the possible outcomes are shown in the below table.

Sample space for two dice

a. Total of 5: $(1+4), (2+3), (3+2), (4+1)$. Number of events is 4.

The probability of getting a total of 5:

$$P = \frac{4}{36} = \frac{1}{9}.$$

b.

At most 4 consists of the following outcomes: $(1+1), (1+2), (1,3), (2,1), (2+2), (3+1)$. Number of events is 6.

The probability of getting at most 4:

$$P = \frac{6}{36} = \frac{1}{6}.$$

Answer: $a \frac{1}{9}; b \frac{1}{6}$.

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