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Answer to Question #6164 in Statistics and Probability for Jane
Question #6164
QUESTION 2. Find the number of possible choices for a 2-digit password that is greater than 19. Then find the number of possible choices for a 4-digit Personal Identification Number (PIN) if the digits cannot be repeated.
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The number of possible choices for a 3-digit PIN is {10}_A^{3}=10!/(10-3)!=10!/7!=10*9*8=720 if the digits cannot be repeated.
Find the number of possible choices for a 3-digit PIN (personal identification number) if the digits cannot be repeated.
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