Question #61545

7 The following are graphical presentations except
chart
none of the above
pictogram
bar chart
8 The difference between Largest and Lowest values on a set of observation is called
range
median
mean
mode
9 Find the mean deviation of the distribution 12,6,7,3,15,10,18,5
4.25
2.97
4.05
4.38
10 Find the standard deviation of the distribution 12,6,7,3,15,10,18,5
4.87
4.97
2.21
5.81
1

Expert's answer

2016-08-26T08:47:03-0400

Answer on Question #61545 – Math – Statistics and Probability

Question

7. The following are graphical presentation except chart none of the above pictogram bar chart.

Answer: pictogram

Question

8. The difference between Largest and Lowest values on a set of observation is called range median mean mode

Answer: range.

Question

9. Find the mean deviation of the distribution 12, 6, 7, 3, 15, 10, 18, 5

4.25

2.97

4.05

4.38

Solution

x=12+6+7+3+15+10+18+58=9.5.\overline{x} = \frac{12 + 6 + 7 + 3 + 15 + 10 + 18 + 5}{8} = 9.5.


The mean deviation is


MD=129.5+69.5+79.5+39.5+159.5+109.58+189.5+59.58=4.25.MD = \frac{|12 - 9.5| + |6 - 9.5| + |7 - 9.5| + |3 - 9.5| + |15 - 9.5| + |10 - 9.5|}{8} + \frac{|18 - 9.5| + |5 - 9.5|}{8} = 4.25.


Answer: 4.25.

Question

10. Find the standard deviation of the distribution

12, 6, 7, 3, 15, 10, 18, 5

4.87

4.97

2.21

5.81

Solution

x=12+6+7+3+15+10+18+58=9.5;\overline{x} = \frac{12 + 6 + 7 + 3 + 15 + 10 + 18 + 5}{8} = 9.5;i=18(xix)2=(129.5)2+(69.5)2+(79.5)2+(39.5)2+(159.5)2+(109.5)2+(189.5)2+(59.5)2=190.\sum_{i=1}^{8} (x_i - \overline{x})^2 = (12 - 9.5)^2 + (6 - 9.5)^2 + (7 - 9.5)^2 + (3 - 9.5)^2 + (15 - 9.5)^2 + (10 - 9.5)^2 + (18 - 9.5)^2 + (5 - 9.5)^2 = 190.


The population standard deviation is


σ=18i=18(xix)2=19084.87.\sigma = \sqrt{\frac{1}{8} \cdot \sum_{i=1}^{8} (x_i - \overline{x})^2} = \sqrt{\frac{190}{8}} \approx 4.87.


Answer: 4.87.

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