Question #61544

4 A man kept 6 black, 5 brown and 7 purple shirts in a drawer. What is the probability of his picking a black shirt with his eyes closed ?

711
711

718
718

511
511

13
13
5 In how many ways can the word "HOSPITAL" be arranged?
45040
120
924
40320
6 In how many ways can the word "TOPOLOGY" be arranged
720 ways
56 ways
84 ways
21 ways
1

Expert's answer

2016-08-25T11:39:03-0400

Answer on Question #61544 – Math – Statistics and Probability

Question

4. A man kept 6 black, 5 brown and 7 purple shirts in a drawer. What is the probability of his picking a black shirt with his eyes closed?

7/11

7/18

5/11

1/3

Solution

The number of black shirts is 6 and the total number of shirts is 18 (6+5+7=18), then the probability of his picking a black shirt with his eyes closed is


P=618=13P = \frac{6}{18} = \frac{1}{3}


Answer: 13\frac{1}{3}.

Question

5. In how many ways can the word "HOSPITAL" be arranged?

45040

120

924

40320

Solution

The word "HOSPITAL" consists of 8 different letters.

Number of ways is


P8=8!=87654321=40320P_8 = 8! = 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 = 40320


Answer: 40320.

Question

6. In how many ways can the word "TOPOLOGY" be arranged?

6720 ways

56 ways

84 ways

21 ways

Solution

The word "TOPOLOGY" contains 1 letter "T", 3 letters "O", 1 letter "P", 1 letter "L", 1 letter "G" and 1 letter "Y". Use the formula of the number of multiset permutations:


P(1,3,1,1,1,1)=8!1!3!1!1!1!1!=87654321321=87654=6720P(1,3,1,1,1,1) = \frac{8!}{1! \cdot 3! \cdot 1! \cdot 1! \cdot 1! \cdot 1!} = \frac{8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{3 \cdot 2 \cdot 1} = 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 = 6720


Answer: 6720 ways.

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