Question #60734

You have been asked to compare two neighbourhoods in the west end of Montreal by a real estate agency. The agency wants to know if a difference exists in the selling price of houses on Westminster street (Montreal West), as compared to Beaconsfield street (NDG). You take a sample of houses sold on both streets over the past 10 years, adjust the inflation and monetary rate so as to equalize the dollar, and tabulate your results. Is there enough evidence to prove that the selling price for the houses on the two streets is significantly different? Please conduct a complete hypothesis test at the 99% confidence level and calculate the p-value. (Hint: Can we assume that the variances are equal?)

Street n x s
Westminister 16 125,950 2400
Beaconsfield 24 128,800 3700
1

Expert's answer

2016-07-07T08:40:02-0400

Answer on Question #60734 – Math – Statistics and Probability

Question

You have been asked to compare two neighbourhoods in the west end of Montreal by a real estate agency. The agency wants to know if a difference exists in the selling price of houses on Westminster street (Montreal West), as compared to Beaconsfield street (NDG). You take a sample of houses sold on both streets over the past 10 years, adjust the inflation and monetary rate so as to equalize the dollar, and tabulate your results. Is there enough evidence to prove that the selling price for the houses on the two streets is significantly different? Please conduct a complete hypothesis test at the 99% confidence level and calculate the p-value. (Hint: Can we assume that the variances are equal?)

Street n x s

Westminster 16 125,950 2400

Beaconsfield 24 128,800 3700

Solution


μw=125950, sw=2400, nw=16;μb=128800, sb=3700, nb=24.\begin{array}{l} \mu_w = 125950, \ s_w = 2400, \ n_w = 16; \\ \mu_b = 128800, \ s_b = 3700, \ n_b = 24. \end{array}


Null hypothesis H0H_0: μw=μb\mu_w = \mu_b.

Alternative hypothesis HaH_a: μwμb\mu_w \neq \mu_b.

Test statistic t=μwμdsw2nw+sd2nd=1259501288002400216+37002/24=2.95t = \frac{\mu_w - \mu_d}{\sqrt{\frac{s_w^2}{n_w} + \frac{s_d^2}{n_d}}} = \frac{125950 - 128800}{\sqrt{\frac{2400^2}{16} + 3700^2 / 24}} = -2.95

Degrees of freedom df=(sw2nw+sd2nd)2sw4nw2(nw1)+sd4nd2(nd1)=(2400216+3700224)22400416215+3700424223=37df = \frac{\left(\frac{s_w^2}{n_w} + \frac{s_d^2}{n_d}\right)^2}{\frac{s_w^4}{n_w^2(n_w - 1)} + \frac{s_d^4}{n_d^2(n_d - 1)}} = \frac{\left(\frac{2400^2}{16} + \frac{3700^2}{24}\right)^2}{\frac{2400^4}{16^2*15} + \frac{3700^4}{24^2*23}} = 37

For t=2.95t = -2.95, df=37df = 37, in two-tailed test p=0.0055<α=0.01p = 0.0055 < \alpha = 0.01.

Therefore, we should reject the null hypothesis and conclude that there is a significant difference in selling prices between Westminster and Beaconsfield.

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