Question #60572

 Determine the direction of the hypothesis test (one-sided left, one-sided right, bidirectional)
 Determine the test statistic (z* or t*) and the p-value for each of the following situations and
 Determine if they would cause the rejection of the null hypothesis if the confidence level was set
at 95% in each case. (Hint: be wary of the sample size) [2 points each]:
a) Ho: μ = 50 mL, Ha: μ ≠ 50 mL, sample mean = 48.1 mL, sample standard deviation = 5, n = 40
b) Ho: μ ≤ 8.4 m3, Ha: μ > 8.4 m3, sample mean = 10 m3, s = 3.5, n = 25
c) Ho: μ ≥ 20oC, Ha: μ < 20oC , sample mean = 17.1oC, s =4.6oC, n = 12
d) Ho: μ = 357 s, Ha: μ ≠ 380 s, sample mean = 410 s, s = 75, n = 40
e) Ho: μ ≤ 46 units, Ha: μ > 46 units, sample mean = 50 units, s = 9.5, n = 41
1

Expert's answer

2016-06-27T09:54:02-0400

Answer on Question #60572 – Math – Statistics and Probability

Question

- Determine the direction of the hypothesis test (one-sided left, one-sided right, bidirectional)

- Determine the test statistic (zz^* or tt^*) and the p-value for each of the following situations and

- Determine if they would cause the rejection of the null hypothesis if the confidence level was set at 95% in each case. (Hint: be wary of the sample size) [2 points each]:

a) Ho: μ=50 mL\mu = 50 \text{ mL}, Ha: μ50 mL\mu \neq 50 \text{ mL}, sample mean = 48.1 mL, sample standard deviation = 5, n = 40

b) Ho: μ8.4 mL\mu \leq 8.4 \text{ mL}, Ha: μ>8.4 mL\mu > 8.4 \text{ mL}, sample mean = 10 mL, s = 3.5, n = 25

c) Ho: μ20 oC\mu \geq 20 \text{ oC}, Ha: μ<20 oC\mu < 20 \text{ oC}, sample mean = 17.1 oC, s = 4.6 oC, n = 12

d) Ho: μ=357 s\mu = 357 \text{ s}, Ha: μ380 s\mu \neq 380 \text{ s}, sample mean = 410 s, s = 75, n = 40

e) Ho: μ46\mu \leq 46 units, Ha: μ>46\mu > 46 units, sample mean = 50 units, s = 9.5, n = 41

Solution

a) Bidirectional;

test statistic (tt^*):


t=xˉμsn=48.150540=2.40;t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}} = \frac{48.1 - 50}{\frac{5}{\sqrt{40}}} = -2.40;


p-value is p=0.021<0.05p = 0.021 < 0.05.

Reject the null hypothesis.

b) One-sided right;

test statistic (tt^*):


t=xˉμsn=108.43.525=2.29;t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}} = \frac{10 - 8.4}{\frac{3.5}{\sqrt{25}}} = 2.29;


p-value is p=0.016<0.05p = 0.016 < 0.05.

Reject the null hypothesis.

c) One-sided left;

Test statistic (tt^*):


t=xˉμsn=17.1204.612=2.18;t = \frac {\bar {x} - \mu}{\frac {s}{\sqrt {n}}} = \frac {17.1 - 20}{\frac {4.6}{\sqrt {12}}} = -2.18;


p-value is p=0.026<0.05p = 0.026 < 0.05.

Reject the null hypothesis.

d) Bidirectional;

Test statistic (t)(t^*):


t=xˉμsn=4103807540=2.53;t = \frac {\bar {x} - \mu}{\frac {s}{\sqrt {n}}} = \frac {410 - 380}{\frac {75}{\sqrt {40}}} = 2.53;


p-value is p=0.016<0.05p = 0.016 < 0.05.

Reject the null hypothesis.

e) One-sided right;

Test statistic (t)(t^*):


t=xˉμsn=50469.541=2.70;t = \frac {\bar {x} - \mu}{\frac {s}{\sqrt {n}}} = \frac {50 - 46}{\frac {9.5}{\sqrt {41}}} = 2.70;


p-value is p=0.005<0.05p = 0.005 < 0.05.

Reject the null hypothesis.

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