Question #60350

Crispy Chips is a potato chip company that is quite popular for its low-fat, low-calorie bags of potato chips. The procedure used at its production plant allows for 65 chips to be inserted into each bag for distribution to consumers. However, given that chip-making is not an exact science, there is a standard deviation of 5 chips per individual bag. If we can assume that the amount of chips in each bag forms a normal distribution, calculate the following:
a) Calculate the z-score if there are 75 chips in a bag.
b) What is the probability that less than 61 potato chips will be in a bag?
c) Determine the probability that more than 79 potato chips will be in a bag.
d) Find the probability that there will be between 60 and 80 potato chips in a bag.
1

Expert's answer

2016-06-13T12:29:03-0400

Answer on Question #60350 – Math – Statistics and Probability

Question

Crispy Chips is a potato chip company that is quite popular for its low-fat, low-calorie bags of potato chips. The procedure used at its production plant allows for 65 chips to be inserted into each bag for distribution to consumers. However, given that chip-making is not an exact science, there is a standard deviation of 5 chips per individual bag. If we can assume that the amount of chips in each bag forms a normal distribution, calculate the following:

a) Calculate the z-score if there are 75 chips in a bag.

b) What is the probability that less than 61 potato chips will be in a bag?

c) Determine the probability that more than 79 potato chips will be in a bag.

d) Find the probability that there will be between 60 and 80 potato chips in a bag.

Solution

a) The z-score is


z(75)=(7565)/5=2.z(75) = (75 - 65)/5 = 2.


b) The z-score is


z(61)=(6165)/5=0.8.z(61) = (61 - 65)/5 = -0.8.


The probability that less than 61 potato chips will be in a bag is


P(X<61)=P(z<0.8)=0.2119.P(X < 61) = P(z < -0.8) = 0.2119.


c) The z-score is


z(79)=(7965)/5=2.8.z(79) = (79 - 65)/5 = 2.8.


The probability that more than 79 potato chips will be in a bag is


P(X>79)=P(z>2.8)=0.0026.P(X > 79) = P(z > 2.8) = 0.0026.


d) The z-scores are


z(60)=(6065)/5=1;z(80)=(8065)/5=3.z(60) = (60 - 65)/5 = -1; \quad z(80) = (80 - 65)/5 = 3.


The probability that there will be less than 60 potato chips in a bag is


P(X<60)=P(z<1)=0.1587.P(X < 60) = P(z < -1) = 0.1587.


The probability that there will be less than 80 potato chips in a bag is


P(X<80)=P(z<3)=0.9987.P(X < 80) = P(z < 3) = 0.9987.


The probability that there will be between 60 and 80 potato chips in a bag is


P(60<X<80)=P(1<z<3)=P(z<3)P(z<1)=0.99870.1587=0.8400.P(60 < X < 80) = P(-1 < z < 3) = P(z < 3) - P(z < -1) = 0.9987 - 0.1587 = 0.8400.


Answer: a) 2; b) 0.2119; c) 0.0026; d) 0.9987.

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