Question #57326

Test scores of ten individuals before and after a training program are shown below.

Individual - Score After Program - Score Before Program
1 - 57 - 59
2 - 62 - 57
3 - 60 - 60
4 - 63 - 66
5 - 69 - 68
6 - 63 - 59
7 - 74 - 72
8 - 56 - 52
9 - 64 - 58
10 - 64 - 63

What is the sum of positive signed ranks (T+)?

The mean µT is?

The value of σT is?

At α = 0.05, what can be concluded about the effectiveness of the training program?

At α = 0.2, what can be concluded about the effectiveness of the training program?
1

Expert's answer

2016-01-15T10:07:06-0500

Answer on Question #57326 - Math - Statistics and Probability

Test scores of ten individuals before and after a training program are shown below.


Question

What is the sum of positive signed ranks (T+)(T^{+})

Solution

T+=8+1.5+6.5+3.5+6.5+9+1.5=36.5T ^ {+} = 8 + 1. 5 + 6. 5 + 3. 5 + 6. 5 + 9 + 1. 5 = 3 6. 5

Question

The mean μT\mu_T is?

Solution

Using Large Sample Approximation to Signed-Rank Statistic


μT=n(n+1)4=9(9+1)4=22.5\mu_ {T} = \frac {n (n + 1)}{4} = \frac {9 (9 + 1)}{4} = 2 2. 5

Question

The value of σT\sigma_T is?

Solution

Using Large Sample Approximation to Signed-Rank Statistic


σT=n(n+1)(2n+1)24=9(9+1)(29+1)24=8.44\sigma_ {T} = \sqrt {\frac {n (n + 1) (2 n + 1)}{2 4}} = \sqrt {\frac {9 (9 + 1) (2 \cdot 9 + 1)}{2 4}} = 8. 4 4

Question

At α=0.05\alpha = 0.05 , what can be concluded about the effectiveness of the training program?

Solution

Let H0H_0 : No difference before and after a training program

H1H_{1} : Scores after a training program are better than before

Using Large Sample Approximation to Signed-Rank Statistic


z=T+μTσT=36.522.58.44=1.659.z = \frac {T ^ {+} - \mu_ {T}}{\sigma_ {T}} = \frac {36.5 - 22.5}{8.44} = 1.659.


The p-value is


P(Z>1.659)=0.048558.P(Z > 1.659) = 0.048558.


Since p-value is less than alpha, we reject H0H_0 and we can conclude that the training program was effective.

**Question**

At α=0.2\alpha = 0.2, what can be concluded about the effectiveness of the training program?

**Solution**

Reject H0H_0, hence the training program was effective.

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