Answer to Question #55538 in Statistics and Probability for John

Question

Two-sample T for LeanBodyMass

Sex N Mean StDev SE Mean
Male 75 52.63 6.66 0.77
Female 75 43.42 6.05 0.70

Difference = μ (Male) - μ (Female)
Estimate for difference: 9.21
95% CI for difference: (-, -)
T-Test of difference = 0 (vs ≠): T-Value = - P-Value = - DF = -
Both use Pooled StDev = 6.3633





Two-sample T for MetRate
SE
Sex N Mean StDev Mean
Male 75 1626 227 26
Female 75 1258 172 20

Difference = μ (Male) - μ (Female)
Estimate for difference: 367.9
95% CI for difference: (-, -)
T-Test of difference = 0 (vs ≠): T-Value = - P-Value = - DF = -
Both use Pooled StDev = 201.5088

b. Calculate a 95% confidence interval to estimate the difference between the average lean body mass of adolescent males and the lean body mass of adolescent females