Question #55356

The probabilities of a boy passing English and Mathematics tests are a and b respectively. Find the probability of the boy failing both tests.
1

Expert's answer

2015-10-08T09:27:31-0400

Answer on Question #55356 – Math – Statistics and Probability

Question

The probabilities of a boy passing English and Mathematics tests are a and b respectively. Find the probability of the boy failing both tests.

Solution

If probability of a boy passing English test is


Prob(English pass)=a,Prob(English\ pass) = a,


then probability of a boy failing English test is


Prob(English fail)=1Prob(English pass)=1a,Prob(English\ fail) = 1 - Prob(English\ pass) = 1 - a,


because it is always the case that either boy passes the test or fails it.

Thus, by the complement rule for probability,


Prob(English pass)+Prob(English fail)=1.Prob(English\ pass) + Prob(English\ fail) = 1.


Similarly, if probability of a boy passing Mathematics test is


Prob(Mathematics pass)=b,Prob(Mathematics\ pass) = b,


then probability of a boy failing Mathematics test is


Prob(Mathematics fail)=1Prob(Mathematics pass)=1b.Prob(Mathematics\ fail) = 1 - Prob(Mathematics\ pass) = 1 - b.


So, according to the multiplication rule of probability for independent events,

the probability of failing both test is


Prob(both fail)=Prob(English fail and Mathematics fail)==Prob(English fail)Prob(Mathematics fail)=(1a)(1b).\begin{array}{l} Prob(both\ fail) = Prob(English\ fail\ and\ Mathematics\ fail) = \\ = Prob(English\ fail) \cdot Prob(Mathematics\ fail) = (1 - a)(1 - b). \end{array}


This is true, because events “English fail” and “Mathematics fail” are independent (no event implies or influences the result of the other).

Answer: (1a)(1b)(1 - a)(1 - b).

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