Question #55259

According to The World Bank, only 9% of the population of Uganda had access to electricity as of 2009. Suppose we randomly sample 150 people in Uganda. Let X = the number of people who have access to electricity.
a. What is the probability distribution for X?
b. Using the formulas, calculate the mean and standard deviation of X.
c. Use your calculator to find the probability that 15 people in the sample have access to electricity.
d. Find the probability that at most ten people in the sample have access to electricity.
e. Find the probability that more than 25 people in the sample have access to electricity.
1

Expert's answer

2015-10-06T09:24:08-0400

Answer on Question #55259 – Math – Statistics and Probability

According to The World Bank, only 9% of the population of Uganda had access to electricity as of 2009. Suppose we randomly sample 150 people in Uganda. Let X=X = the number of people who have access to electricity.

a. What is the probability distribution for XX?

b. Using the formulas, calculate the mean and standard deviation of XX.

c. Use your calculator to find the probability that 15 people in the sample have access to electricity.

d. Find the probability that at most ten people in the sample have access to electricity.

e. Find the probability that more than 25 people in the sample have access to electricity.

Solution

a. In this case we are given sample size nn and probability pp so this is a binomial distribution with n=150n = 150 and p=0.09p = 0.09.

b. The mean of XX is


μ=np=0.09150=13.5.\mu = n p = 0.09 \cdot 150 = 13.5.


A standard deviation is


σ=np(1p)=0.09150(10.09)=3.5.\sigma = \sqrt{n p (1 - p)} = \sqrt{0.09 \cdot 150 (1 - 0.09)} = 3.5.


c. The probability that 15 people in the sample have access to electricity


binomialpdf(150;0.09;15)=150!15!(15015)!0.0915(10.09)5015=0.0988.\text{binomialpdf}(150; 0.09; 15) = \frac{150!}{15! (150 - 15)!} \cdot 0.09^{15} (1 - 0.09)^{50 - 15} = 0.0988.


In Excel 2007 and earlier it is calculated by


=BINOMDIST(15;150;0.09;FALSE)= \text{BINOMDIST}(15; 150; 0.09; \text{FALSE})


In Excel 2010 and later it is calculated by


=BINOM.DIST(15;150;0.09;FALSE)= \text{BINOM.DIST}(15; 150; 0.09; \text{FALSE})


d. The probability that at most ten people in the sample have access to electricity is the cumulative binomial probability with n=150n = 150, p=.09p = .09, and x=10x = 10 is


binomialcdf(150;0.09;10)=k=010150!k!(150k)!0.09k(10.09)50k=0.1987.\text{binomialcdf}(150; 0.09; 10) = \sum_{k=0}^{10} \frac{150!}{k! (150 - k)!} \cdot 0.09^k (1 - 0.09)^{50 - k} = 0.1987.


In Excel 2007 and earlier it is calculated by


=BINOMDIST(10;150;0.09;TRUE)= \text{BINOMDIST}(10; 150; 0.09; \text{TRUE})


In Excel 2010 and later it is calculated by


=BINOM.DIST(10;150;0.09;TRUE)= \text{BINOM.DIST}(10; 150; 0.09; \text{TRUE})


e. The cumulative binomial probability of having at most 25 people have electricity (n=150, p=.09, x=25) is


binomialcdf(150;0.09;25)=k=025150!k!(150k)!0.09k(10.09)50k=0.9991.b i n o m i a l c d f (1 5 0; 0. 0 9; 2 5) = \sum_ {k = 0} ^ {2 5} \frac {1 5 0 !}{k ! (1 5 0 - k) !} 0. 0 9 ^ {k} (1 - 0. 0 9) ^ {5 0 - k} = 0. 9 9 9 1.


In Excel 2007 and earlier it is calculated by


=BINOMDIST(25;150;0,09;TRUE)= B I N O M D I S T (2 5; 1 5 0; 0, 0 9; T R U E)


In Excel 2010 and later it is calculated by


=BINOM.DIST(25;150;0,09;TRUE)= B I N O M. D I S T (2 5; 1 5 0; 0, 0 9; T R U E)


So the probability of having more than 25 people is


10.9991=0.0009.1 - 0. 9 9 9 1 = 0. 0 0 0 9.


www.AssignmentExpert.com


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS