Question #55136

The chances that a visit to a primary health centre (PHC) results in neither lab
work, nor referred to a specialist is 35%. Out of those coming to a PHC, 30% are
referred to a specialist, and 40% require lab work. Find the probability that a visit
to a PHC results in both lab work and referral to a specialist.
1

Expert's answer

2015-10-14T00:10:02-0400

Answer on Question #55136 – Math – Statistics and Probability

The chances that a visit to a primary health centre (PHC) results in neither lab work, nor referred to a specialist is 35%. Out of those coming to a PHC, 30% are referred to a specialist, and 40% require lab work. Find the probability that a visit to a PHC results in both lab work and referral to a specialist.

Solution

Consider the following events: R=R = "referral to a specialist", L=L = "lab work".

We shall use the two formulae:


P[RL]=P[R]+P[L]P[RL](rule of addition)P[R \cup L] = P[R] + P[L] - P[R \cap L] \quad \text{(rule of addition)}1P[(RL)]=P[RL](rule of subtraction)1 - P[\overline{(R \cup L)}] = P[R \cup L] \quad \text{(rule of subtraction)}


We want to find


P[RL]=P[R]+P[L]P[RL]=P[R]+P[L]1+P[(RL)]==P[R]+P[L]1+P[RˉLˉ]=0.30+0.401+0.35=0.05.\begin{aligned} P[R \cap L] &= P[R] + P[L] - P[R \cup L] = P[R] + P[L] - 1 + P[\overline{(R \cup L)}] = \\ &= P[R] + P[L] - 1 + P[\bar{R} \cap \bar{L}] = 0.30 + 0.40 - 1 + 0.35 = 0.05. \end{aligned}


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