Answer to Question #53370 in Statistics and Probability for Bob

Question #53370

Given z is a standard normal random variable, answer questions 1 through 4.

1. p(z = 2.3) is

a. .1056.
b. 0.
c. .8944.
d. .3944.

2. p(z ≥ -1.84) is

a. .5474.
b. 0.
c. .0329.
d. .9671.

3. p(z ≤ 1.4) is

a. .0808.
b. .9192.
c. .9927.
d. 0.

4. p(.5 ≤ z ≤ 2.9) is

a. 0.
b. .6915.
c. .3066.
d. 9981.

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Assignment Expert

27.06.18, 23:01

The solution uses the standard normal distribution table in calculations (see https://math.arizona.edu/~rsims/ma464/standardnormaltable.pdf). There exist normal distribution calculators (for example, https://www.mathportal.org/calculators/statistics-calculator/normal-distribution-calculator.php). In this problem the standard normal random variable is given, hence the mean is 0 and the standard deviation is 1.

jamie

27.06.18, 19:08

how do you punch the answer into the calculator?

Answer to Question #53370 in Statistics and Probability for Bob

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