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Answer to Question #52391 in Statistics and Probability for Bob
Question #52391
Customers arrive at a particular store at the rate of 30 customers per hour.
1. What is the probability of 15 customers arriving in an hour?
a. .500
b. .001
c. .617
d. .100
2. What is the probability of 10 customers arriving in a 20-minute interval?
a. .500
b. .000
c. .125
d. 1.00
3. What is the probability of at least 2 customers arriving in a 5-minute interval?
a. .257
b. .713
c. .743
d. .287
4. What is the probability of 3 customers arriving in a 5-minute interval?
a. .000
b. .214
c. .500
d. .100
1. What is the probability of 15 customers arriving in an hour?
a. .500
b. .001
c. .617
d. .100
2. What is the probability of 10 customers arriving in a 20-minute interval?
a. .500
b. .000
c. .125
d. 1.00
3. What is the probability of at least 2 customers arriving in a 5-minute interval?
a. .257
b. .713
c. .743
d. .287
4. What is the probability of 3 customers arriving in a 5-minute interval?
a. .000
b. .214
c. .500
d. .100
Expert's answer
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Comments
It is given that the mean in the hour interval (that is, 60-minutes interval) is 30,then 30/60=0.5 is the mean in the 1-minute interval and 30/60*5=0.5*5=2.5 is the mean in the 5-minutes interval.
I am working on question "what is the probability of 3 customers arriving in a 5 min interval?" Looking at the solution, where does the 2.5 come from?
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