Answer to Question #4977 in Statistics and Probability for Jennifer Ashmore

Question #4977

A contractor decided to build homes that will include the middle 80% of the market. If the average size of the hoomes built is 1810 square feet, find the maximum and minimum sizes of the homes the contractor should build. Assume that the standard deviation is 92 square feet and the variable is normally distributed.

Expert's answer

sd = 92, a = 1810, P = 0.8
P(Xmin<=X<Xmax) = Ф((Xmax-a)/sd)
- Ф((Xmin-a)/sd),
0<=X<4
0.8 = 0.4 - (-0.4)
(Xmax-a)/sd = 0.4,
(Xmax-1810)/92 = 0.4, Xmax = 1810+36.8 = 1846.8 square feet, Xmin = 1810 - 36.8
= 1773.2 square feet

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Assignment Expert

24.02.21, 16:14

Dear Jovert, please use the panel for submitting a new question.

Assignment Expert

24.02.21, 16:13

Dear Dulce, a solution describes that 0.8=0.4-(-0.4).

Jovert

15.02.21, 03:31

A contractor builds houses that include the 50% of the market. The average size of the houses he builds is 80 square meters and the standard deviation is 10 square meters. Assume that the variable is normally distributed, what are the maximum and minimum sizes of houses he should build?

Dulce

21.10.20, 08:37

Where did 0.8 come from? And how did you find 0.8?

Answer to Question #4977 in Statistics and Probability for Jennifer Ashmore

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