Answer on Question #49745 – Math – Statistics and Probability
After the quizzes are marked, you're told that the scores on the exam were distributed normally (μ=50, σ=10). You are also told that students with scores in the top 10% will receive a chocolate bar, and students with scores in the top 25% will receive a stick of gum.
a) What is the minimum score needed to receive a chocolate bar?
b) Would a score of 57 earn a stick of gum?
Solution
We need to convert the normal distribution to the standard normal distribution:
Z=σx−μ.
a) P(X>x1)=P(Z>z1)=1−P(Z<z1)=0.1→P(Z<z1)=0.9.
Then from normal table, z1=2.33.
So
z1=σx1−μ→x1=μ+z1σ=50+2.33⋅10=73.3.Answer: 73.3.
b) P(Z>z)=P(Z>σx1−μ)=P(Z>1057−50)=P(Z>0.7)=1−P(Z<0.7).
Then from normal table,
P(Z<0.7)=0.7580.
And
P(Z>z)=1−0.758=0.242<0.25.
Hence a score of 57 would earn a stick of gum.
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