Answer to Question #49423 in Statistics and Probability for themer

Question

A plumber loads his truck each morning with faucets that will be needed for the service calls and other emergency calls that come in that day. Based on past experience, the number of faucets required each day (N) has the following distribution: p(0) =0.05; p(1) = 0.25;
p(2) = 0.5; p(3) = 0.15; p(4) = 0.05.


-Each faucet requires 25 minutes to install. What is the expected number of minutes the plumber will spend each day installing faucets?

Answer 1

As the number of faucets required each day (N) has the following distribution:
p(0) =0.05; p(1) = 0.25; p(2) = 0.5; p(3) = 0.15; p(4) = 0.05 and each faucet requires 25 minutes to install.
The expected number of minutes the plumber will spend each day installing faucets is
T = 25*(0*0.05 + 1*0.25 + 2*0.5 + 3*0.15 + 4*0.05) = 47.5 minutes.