Question

There are 6 cherries, 3 oranges and 2 lemon candies. What is the probability of getting 3 cherries ?

Answer 1

Answer on Question #49000 – Math – Statistics and Probability

There are 6 cherries, 3 oranges and 2 lemon candies. What is the probability of getting 3 cherries?

Solution.

The event A – ``we get 3 cherries''.

$$P(A) = \frac{m}{n};$$ $$n = C(11, 3) = \frac{11!}{8!3!} = 165;$$ $$m = C(6, 3) = \frac{6!}{3!3!} = 20;$$ $$P(A) = \frac{20}{165} = \frac{4}{33} \approx 0.12$$

Answer: $P(A) \approx 0.12$

www.AssignmentExpert.com