Answer on Question #48984 – Math – Statistics and Probability
The table below gives two samples selected from 10 supermarkets of the weekly sales of a popular soft drink. The first sample gives the details for a normal shelf display of the product, while the second sample gives the details for an end-aisle shelf display. Assuming equal variances, establish, at the 5% level of significance, whether there is a statistically significant difference in the mean weekly sales for the two display locations.
Normal display: 22,34,52,62,30,40,64,84,56,59
END AISLE DISPLAY: 52,71,76,54,67,83,66,90,77,84
Solution
H0:μ1=μ2;H1:μ1=μ2.
xˉ=n∑xi=10503=50.3.yˉ=n∑yi=10720=72.sxˉ2=n−1∑xi2−nxˉ2=928457−10⋅50.32=350.7.syˉ2=n−1∑yi2−nyˉ2=953256−10⋅722=157.3.
Assuming equal variances, the t Statistic:
t = \frac{\bar{y} - \bar{x}}{\sqrt{\frac{(n-1)s_{\bar{x}}^2 + (n-1)s_{\bar{y}}^2}{(n-1) + (n-1)}} = \frac{\bar{y} - \bar{x}}{\sqrt{\frac{s_{\bar{x}}^2 + s_{\bar{y}}^2}{2}}} = \frac{72 - 50.3}{\sqrt{\frac{350.7 + 157.3}{2}}} = 1.36.
Critical value for n−1=10−1=9 degrees of freedom and 5% level of significance is t∗=2.262.
Critical region: t>2.262.
We don't reject H0 because test statistic t=1.36<2.262. There is no statistically significant difference in the mean weekly sales for the two display locations.
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