Question #48500

If Z is a standard normal variable, find the probability.
P(Z > 0.59)
1

Expert's answer

2014-11-03T11:26:48-0500

Answer on Question #48500 – Math – Statistics and Probability

Question.

If ZZ is a standard normal variable, find the probability P(Z>0.59)P(Z > 0.59).

Solution.

We shall use the tabulated function of Laplace: Φ(x)=12π0xeu22du\Phi(x) = \frac{1}{\sqrt{2\pi}} \int_{0}^{x} e^{-\frac{u^2}{2}} du. The required probability is equal to P(Z>0.59)=0.5Φ(0.59)=0.50.2224=0.2776P(Z > 0.59) = 0.5 - \Phi(0.59) = 0.5 - 0.2224 = 0.2776.

Answer. 0.2776.

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