Question #48470

A certain bond fund over the last 12 years has had a mean yearly return of 5.9% with a standard deviation of 1.8%.
A. If you had invested in this fund over the past 12 years, in how many of these years would you expect to have learned at least 8% on your investment?
B. In how many years would you expect to have earned less than 4%?
1

Expert's answer

2014-11-05T08:32:00-0500

Answer on Question #48470 – Math – Statistics and Probability

A certain bond fund over the last 12 years has had a mean yearly return of μ=5.9%\mu = 5.9\% with a standard deviation of σ=1.8%\sigma = 1.8\%.

A. If you had invested in this fund over the past 12 years, in how many of these years would you expect to have learned at least 8%8\% on your investment?

B. In how many years would you expect to have earned less than 4%4\%?

Solution

A. The ratio of years in which I learned at least 8%8\% on your investment is


P(X>8%)=P(z>8%5.9%1.8%)=P(z>1.17)=1P(z<1.17).P(X > 8\%) = P\left(z > \frac{8\% - 5.9\%}{1.8\%}\right) = P(z > 1.17) = 1 - P(z < 1.17).


From z-table we know:


P(z<1.17)=0.8790.P(z < 1.17) = 0.8790.


That's why


P(X>8%)=10.8790=0.121.P(X > 8\%) = 1 - 0.8790 = 0.121.


The number of years in which I learned at least 8%8\% on your investment is


120.121=1.45.12 \cdot 0.121 = 1.45.


B. The ratio of years in which I expect to have earned less than 4%4\% is


P(X<8%)=P(z<4%5.9%1.8%)=P(z<1.06).P(X < 8\%) = P\left(z < \frac{4\% - 5.9\%}{1.8\%}\right) = P(z < -1.06).


From z-table we know:


P(z<1.06)=0.1446.P(z < -1.06) = 0.1446.


The number of years in which I expect to have earned less than 4%4\% is


120.1446=1.74.12 \cdot 0.1446 = 1.74.


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