Question

10 From the set A={3, √2, √23, √9,√7},a number is selected at random. Find the probability that is a rational number.

1/5
2/5
3
4

Answer 1

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Answer on Question #47201 – Math – Statistics and Probability

From the set $A = \{3, \sqrt{2}, \sqrt{23}, \sqrt{9}, \sqrt{7}\}$, a number is selected at random. Find the probability that is a rational number.

1/5

2/5

3

4

Solution.

There are 2 rational numbers $(3, \sqrt{9} = 3)$ and 3 irrational numbers $(\sqrt{2}, \sqrt{23}, \sqrt{7})$ in the set of 5 numbers.

Thus, the probability that a number is selected at random is a rational number equals $\frac{2}{5}$.