Question #46861

Because of economic conditions, a firm reports that 30% of its accounts receivable from other business firm are overdue. If an accountant takes a random sample of five such accounts, determine the probability that at least two accounts is overdue.
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Expert's answer

2014-09-25T12:23:49-0400

Answer on Question #46861 – Math – Statistics and Probability

Problem.

Because of economic conditions, a firm reports that 30% of its accounts receivable from other business firm are overdue. If an accountant takes a random sample of five such accounts, determine the probability that at least two accounts is overdue.

Solution:

The probability that an account is overdue equals p=30100=0.3p = \frac{30}{100} = 0.3.

The probability that an account isn't overdue equals q=1p=10.3=0.7q = 1 - p = 1 - 0.3 = 0.7.

The probability that in the sample of five accounts no accounts is overdue equals


P0=(50)p0q5=q5=0.75P_0 = \binom{5}{0} p^0 q^5 = q^5 = 0.7^5


by Bernoulli’s trial.

The probability that in the sample of five accounts exactly one account is overdue equals


P1=(51)p1q4=50.3(0.7)4P_1 = \binom{5}{1} p^1 q^4 = 5 \cdot 0.3 \cdot (0.7)^4


by Bernoulli’s trial.

The that in the sample of five accounts less than two accounts is overdue equals


P0+P1.P_0 + P_1.


The that in the sample of five accounts at least two accounts is overdue equals


1(P0+P1)=10.7550.3(0.7)4=0.47178.1 - (P_0 + P_1) = 1 - 0.7^5 - 5 \cdot 0.3 \cdot (0.7)^4 = 0.47178.


Answer: 0.47178.

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