Question #46746

Construct a 95% confidence interval for the population mean, μ. Assume the population has a
normal distribution. A sample of 25 randomly selected students has a mean test score of 81.5 with a
standard deviation of 10.2.
1

Expert's answer

2014-09-23T13:37:06-0400

Answer on Question #46746 – Math – Statistics and Probability

Problem.

Construct a 95% confidence interval for the population mean, μ. Assume the population has a normal distribution. A sample of 25 randomly selected students has a mean test score of 81.5 with a standard deviation of 10.2.

Solution:

For 95% confidence interval z=1.96z^* = 1.96.

The confidence limits for the population mean are equal to μ±zσn\mu \pm z^* \cdot \frac{\sigma}{\sqrt{n}}.

Hence for μ=81.5\mu = 81.5, σ=10.2\sigma = 10.2 and n=25n = 25 we will have interval


(81.510.225,81.5+10.225)=(79.46,83.54)\left(81.5 - \frac{10.2}{\sqrt{25}}, 81.5 + \frac{10.2}{\sqrt{25}}\right) = (79.46, 83.54)


Answer: (79.46, 83.54).

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