Question #46537

Metal conduits or hollow pipes are used in electrical wiring. In testing 1-inch pipes, these data are obtained on the outside diameter (in inches) of the pipe: 1.21, 1.19, 1.20, 1.22, 1.18, 1.23, 1.17, 1.09. Assume that sampling is from normal distribution with mean and variance .
i.Find unbiased estimates for and .
ii.Find 95% confidence interval on the mean outside diameter of pipes of this type.
1

Expert's answer

2014-09-17T13:39:27-0400

Answer on Question #46537 – Math – Statistics and Probability

Problem.

Metal conduits or hollow pipes are used in electrical wiring. In testing 1-inch pipes, these data are obtained on the outside diameter (in inches) of the pipe: 1.21, 1.19, 1.20, 1.22, 1.18, 1.23, 1.17, 1.09. Assume that sampling is from normal distribution with mean and variance.

i. Find unbiased estimates for and .

ii. Find 95% confidence interval on the mean outside diameter of pipes of this type.

Remark: The part of question is missed. I suppose that the correct statement is

"Metal conduits or hollow pipes are used in electrical wiring. In testing 1-inch pipes, these data are obtained on the outside diameter (in inches) of the pipe: 1.21, 1.19, 1.20, 1.22, 1.18, 1.23, 1.17, 1.09. Assume that sampling is from normal distribution with mean μ and variance σ².

i. Find unbiased estimates for μ and σ².

ii. Find 95% confidence interval on the mean outside diameter of pipes of this type."

(see http://www.bits-pilani.ac.in/uploads/ReadPDFDOC/AAOC C111 515 C 2009 2.doc)

Solution:

i. Unbiased estimate for μ equals xˉ=1.21+1.19+1.20+1.22+1.18+1.23+1.17+1.098=1.18625\bar{x} = \frac{1.21 + 1.19 + 1.20 + 1.22 + 1.18 + 1.23 + 1.17 + 1.09}{8} = 1.18625.

Unbiased estimate for σ² equals s2=17((1.21xˉ)2+(1.19xˉ)2+(1.20xˉ)2+(1.22xˉ)2+(1.18xˉ)2+(1.23xˉ)2+(1.17xˉ)2)=0.0019125s^2 = \frac{1}{7}((1.21 - \bar{x})^2 + (1.19 - \bar{x})^2 + (1.20 - \bar{x})^2 + (1.22 - \bar{x})^2 + (1.18 - \bar{x})^2 + (1.23 - \bar{x})^2 + (1.17 - \bar{x})^2) = 0.0019125.

Answer: xˉ=1.18625,s2=0.0019125\bar{x} = 1.18625, s^2 = 0.0019125

ii. For 95% confidence interval z* = 1.96.

The confidence limits for the population mean are equal μ ± z* · σ or 1.1825015 and 1.1899985. The 95% confidence interval is (1.1825015, 1.1899985).

Answer: (1.1825015, 1.1899985).

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