Question #46081

Steel rods are manufactured to be 3 inches in diameter but they are acceptable if they are inside the limit 2.99 inches and 3.01 inches. It is observed that 5% are rejected as oversized and 5% are rejected undersized. Assuming that the diameters are normally distributed, find the standard deviation of the distribution.
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Expert's answer

2014-09-15T10:16:30-0400

Answer on Question #46081 – Math – Statistics and Probability

Steel rods are manufactured to be 3 inches in diameter but they are acceptable if they are inside the limit 2.99 inches and 3.01 inches. It is observed that 5% are rejected as oversized and 5% are rejected undersized. Assuming that the diameters are normally distributed, find the standard deviation of the distribution.

Solution

Let XX denote the diameter of the rods in inches and let XN(μ,σ2)X \sim N(\mu, \sigma^2).

Here we are given


P(X<2.99)=0.05 and P(X>3.01)=0.05P(X < 2.99) = 0.05 \text{ and } P(X > 3.01) = 0.05


It is seen from the above table that the value of ZZ for 10% level of significance is Z=±1.645Z = \pm 1.645, as the 5% rejection region lies in two tails of the normal distribution, then we have


2.99μσ=1.645 and 3.01μσ=1.645\frac{2.99 - \mu}{\sigma} = -1.645 \text{ and } \frac{3.01 - \mu}{\sigma} = 1.6453.01μ=1.645σ and 2.99μ=1.645σ3.01 - \mu = 1.645\sigma \text{ and } 2.99 - \mu = -1.645\sigmaμ=3 and σ=0.006079.\mu = 3 \text{ and } \sigma = 0.006079.


Answer: 0.006079.

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