Question #46076

If A and B are two events with probabilities 0.25 and 0.5 corresponding to A and A∪B respectively, then find the probability of B if (i) A and B are mutually exclusive (ii) A and B are independent (iii) B contains A.
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Expert's answer

2014-09-15T10:11:43-0400

Answer on Question #46076 - Math - Statistics and Probability

If A and B are two events with probabilities 0.25 and 0.5 corresponding to A and A∪B respectively, then find the probability of B if

(i) A and B are mutually exclusive

(ii) A and B are independent

(iii) B contains A.

Solution

(i) If A and B are mutually exclusive, then P(AB)=0P(A \cap B) = 0

P(AB)=P(A)+P(B)P(AB)=P(A)+P(B)P(A \cup B) = P(A) + P(B) - P(A \cap B) = P(A) + P(B)P(B)=P(AB)P(A)=0.50.25P(B) = P(A \cup B) - P(A) = 0.5 - 0.25


(ii) If A and B are independent, then P(AB)=P(A)P(B)P(A \cap B) = P(A) * P(B)

P(AB)=P(A)+P(B)P(AB)=P(A)+P(B)P(A)P(B)P(A \cup B) = P(A) + P(B) - P(A \cap B) = P(A) + P(B) - P(A) * P(B)P(B)=P(AB)P(A)1P(A)=0.50.2510.25=13P(B) = \frac{P(A \cup B) - P(A)}{1 - P(A)} = \frac{0.5 - 0.25}{1 - 0.25} = \frac{1}{3}


(iii) If B contains A, then P(B)=P(AB)=0.5P(B) = P(A \cup B) = 0.5

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