Question #44690

7. A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 875 hours. A random sample of 58 light bulbs has a mean life of 852 hours with a standard deviation of 95 hours. Do you have enough evidence to reject the manufacturer’s claim? Use a = 0.09.
a. Identify the null hypothesis and alternative hypothesis.
b. Identify the critical value (s). Use a comma to separate answers as needed
c. Identify the standardized test statistic.
d. Decide whether to reject or fail to reject the null hypothesis.
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Expert's answer

2014-08-07T08:28:22-0400

Answer on Question #44690 - Math - Statistics and Probability

A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 875 hours. A random sample of 58 light bulbs has a mean life of 852 hours with a standard deviation of 95 hours. Do you have enough evidence to reject the manufacturer's claim?

Use α=0.09\alpha = 0.09.

a. Identify the null hypothesis and alternative hypothesis.

b. Identify the critical value (s). Use a comma to separate answers as needed.

c. Identify the standardized test statistic.

d. Decide whether to reject or fail to reject the null hypothesis.

Solution:

a. Identify the null hypothesis and alternative hypothesis:

The null hypothesis contains "equal" sign ("=" or "≥" or "≤"), the alternative hypothesis is the complement to the null hypothesis. The claim is "the mean life of a certain type of light bulb is at least 875 hours". As the claim contains "≥" sign, it is null hypothesis.

H0:μ875H_0: \mu \geq 875

Alternative hypothesis:

The alternative hypothesis is the complement: "the mean life of a certain type of light bulb is less than 875 hours".

Ha:μ<875H_a: \mu < 875

b. Identify the critical value (s). Use a comma to separate answers as needed

As the alternative hypothesis contains "<" sign, the test is left-tailed. Using α=0.09\alpha = 0.09, we obtain critical value from standard table of normal distribution:

z0=1.34z_0 = -1.34

Thus, the rejection region for the test statistic is z<1.34z < -1.34.

c. Identify the standardized test statistic.

The test statistic is:


z=x^μs/n=85287595/58=1.84z = \frac{\hat{x} - \mu}{s / \sqrt{n}} = \frac{852 - 875}{95 / \sqrt{58}} = -1.84


d. Decide whether to reject or fail to reject the null hypothesis.

As -1.84 < -1.34, we should reject the null hypothesis, so we do not have enough evidence to support the manufacturer's claim.

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