Question #43529

Find the density function of a normally distributed random variable X, if E(X) = 7.8 and σ(X) = 4.1
1

Expert's answer

2014-06-24T03:07:42-0400

Answer on Question #43529-Math-Statistics and Probability

Find the density function of a normally distributed random variable XX, if E(X)=7.8E(X) = 7.8 and σ(X)=4.1\sigma(X) = 4.1.

Solution

The density function of a normally distributed random variable XX is


f(x)=1σ2πe(xμ)22σ2=14.12πe(x7.8)224.12=0.0973e(x7.8)233.62.f(x) = \frac{1}{\sigma\sqrt{2\pi}} e^{-\frac{(x-\mu)^2}{2\sigma^2}} = \frac{1}{4.1\sqrt{2\pi}} e^{-\frac{(x-7.8)^2}{2 \cdot 4.1^2}} = 0.0973 \cdot e^{-\frac{(x-7.8)^2}{33.62}}.


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