Question #42867

Of the Type A electrical resistors produced by a factory, 85% have
resistance greater than 41 ohms, and 3.7% of them have resistance
greater than 45 ohms. The resistances follow a normal distribution.
What percentage of these resistors have resistance greater than 44
ohms?
1

Expert's answer

2014-05-29T10:24:36-0400

Answer on Question #42867 – Math - Statistics and Probability

Of the Type A electrical resistors produced by a factory, 85% have resistance greater than 41 ohms, and 3.7% of them have resistance greater than 45 ohms. The resistances follow a normal distribution. What percentage of these resistors has resistance greater than 44 ohms?

Solution

Pr[Z>z1]=0.85 or Φ(z1)=10.85=0.15.\Pr[Z > z_1] = 0.85 \text{ or } \Phi(z_1) = 1 - 0.85 = 0.15.


from Tables we find z1=1.04z_1 = -1.04.


Pr[Z>z2]=0.037 or Φ(z2)=10.037=0.963.\Pr[Z > z_2] = 0.037 \text{ or } \Phi(z_2) = 1 - 0.037 = 0.963.


from Tables we find z2=1.79z_2 = 1.79.

Then


z1=41μσ=1.04,z2=45μσ=1.79μ=42.48,σ=1.41.z_1 = \frac{41 - \mu}{\sigma} = -1.04, \quad z_2 = \frac{45 - \mu}{\sigma} = 1.79 \rightarrow \mu = 42.48, \quad \sigma = 1.41.


The percentage of these resistors has resistance greater than 44 ohms is


Pr[Z>z3]=Pr[Z>4442.481.41]=Pr[Z>1.078]=1Φ(1.078)=10.859=0.141=14.1%.\Pr[Z > z_3] = \Pr\left[Z > \frac{44 - 42.48}{1.41}\right] = \Pr[Z > 1.078] = 1 - \Phi(1.078) = 1 - 0.859 = 0.141 = 14.1\%.


Answer: 14.1%.

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