Question #42116

A random sample of 30 companies dealing in network products was selected to determine the proportion of such companies that have implemented new software to improve productivity. It turned out that 8 had implemented such software. Find a 95% confidence interval on p, the true proportion of such companies that have implemented new software and how many companies would need to be sampled in order to have a 95% confident that the estimate of p is within 0.05 of the true value?
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Expert's answer

2014-05-08T11:36:47-0400

Answer on Question #42116-Math-Statistics and Probability

A random sample of 30 companies dealing in network products was selected to determine the proportion of such companies that have implemented new software to improve productivity. It turned out that 8 had implemented such software. A) Find a 95% confidence interval on p, the true proportion of such companies that have implemented new software and B) how many companies would need to be sampled in order to have a 95% confident that the estimate of p is within 0.05 of the true value?

Solution

A) n=30,x=8,and z0.025=1.96n = 30, x = 8, \text{and } z_{0.025} = 1.96. So, limits of confidence intervals are


415±(1.96)415111530=415±0.158,\frac{4}{15} \pm (1.96) \sqrt{\frac{\frac{4}{15} \cdot \frac{11}{15}}{30}} = \frac{4}{15} \pm 0.158,


which yields 0.108<p<0.4250.108 < p < 0.425.

B)


n=(1.96)241511150.052=301,when round up.n = \frac{(1.96)^2 \cdot \frac{4}{15} \cdot \frac{11}{15}}{0.05^2} = 301, \text{when round up}.


Answer: A) 0.108<p<0.4250.108 < p < 0.425; B) 301.

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