Question #41885

In a random sample of 40 felons convicted of aggravated assault, it was determined that the
mean length of sentencing was 54 months, with a standard deviation of 8 months. Construct
and interpret a 95% confidence interval for the mean length of sentence for an aggravated
assault conviction.
1

Expert's answer

2014-05-07T13:26:03-0400

Answer on Question #41885 – Math - Statistics and Probability

In a random sample of 40 felons convicted of aggravated assault, it was determined that the mean length of sentencing was 54 months, with a standard deviation of 8 months. Construct and interpret a 95% confidence interval for the mean length of sentence for an aggravated assault conviction.

Solution:

Sample size n = 40 (large sample)

Sample mean xˉ=54\bar{x} = 54

Standard deviation σ=8\sigma = 8

γ=0.95confidence probability\gamma = 0.95 - \text{confidence probability}


Since 1α=0.951 - \alpha = 0.95 , α/2=0.025\alpha / 2 = 0.025 , and z0.025=1.96z_{0.025} = 1.96 , the large sample 95%95\% confidence interval for μ\mu becomes (xˉz2σn;xˉz2σn)=(541.96840;54+1.96840)=(51.52;56.48)\left(\bar{x} - z_2 \frac{\sigma}{\sqrt{n}}; \bar{x} - z_2 \frac{\sigma}{\sqrt{n}}\right) = \left(54 - 1.96 \frac{8}{\sqrt{40}}; 54 + 1.96 \frac{8}{\sqrt{40}}\right) = (51.52; 56.48) .

This means that we can be 95% confident that the mean length of sentencing is in the interval 51.52 to 56.48 months.

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