Question #41822

the values below are the scores (maximum 20) obtained in an aptitude test by a random sample of 11 graduates. it is known that for the non-graduate population the median score is 12. is there evidence, at the 10% significance level, that graduate achieve a higher median score than the non-graduate population?
14 15 09 10 10 13 14 19 12 16 13
1

Expert's answer

2014-05-02T03:35:53-0400

Answer on Question # 41822, Math, Statistics and Probability

The values below are the scores (maximum 20) obtained in an aptitude test by a random sample of 11 graduates. It is known that for the non-graduate population the median score is 12. Is there evidence, at the 10% significance level, that graduate achieve a higher median score than the non-graduate population?

14 15 09 10 10 13 14 19 12 16 13

Solution:

1) H0:η=12H_0: \eta = 12

2) H1:η>12H_1: \eta > 12 (one-tailed)

3) α=0.10\alpha = 0.10 – significance level

4) Signs of (score – 12) are:


+++++0+++ + - - - + + + 0 + +


5) Let XX denote the number of + signs. Then, ignoring the one 0 in this case, under H0H_0,


XB(10,0.5) with observed value of X=7.X \sim B(10, 0.5) \text{ with observed value of } X = 7.


6) B(10,0.5)B(10, 0.5) – binomial distribution with parameters 10 and 0.5

7) P(X7)=i=710(10i)0.5i0.510i=11024i=710(10i)=11024(120+45+9+1)=P(X \geq 7) = \sum_{i=7}^{10} \binom{10}{i} 0.5^i 0.5^{10-i} = \frac{1}{1024} \sum_{i=7}^{10} \binom{10}{i} = \frac{1}{1024} (120 + 45 + 9 + 1) =

=18510240.18>0.1= \frac{185}{1024} \approx 0.18 > 0.1

Answer:

Thus there is no evidence, at the 10% level of significance, to suggest that graduates achieve a higher median score than the non-graduate population.

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