Question #39526

An urn A contains 2 white & 4 black balls. Another urn B contains 5 white & 7 black balls. A ball is transferred from urn A to urn B, then a ball is drawn from urn B. Find the probability that it is white
1

Expert's answer

2014-02-27T05:50:27-0500

Answer on Question #39526 – Math – Statistics and Probability

An urn A contains 2 white & 4 black balls. Another urn B contains 5 white & 7 black balls. A ball is transferred from urn A to urn B, then a ball is drawn from urn B. Find the probability that it is white.

Solution.

Let A,B,CA, B, C be three events:


A={the second ball is white};A = \{ \text{the second ball is white} \};B={the first ball is white};B = \{ \text{the first ball is white} \};C={the first ball is black};C = \{ \text{the first ball is black} \};


We need to find P(A)P(A). Hence:


P(B)=26=13;P(B) = \frac{2}{6} = \frac{1}{3};P(C)=46=23;P(C) = \frac{4}{6} = \frac{2}{3};P(AB)=613;P(A|B) = \frac{6}{13};P(AC)=513;P(A|C) = \frac{5}{13};P(A)=P(AB)+P(AC)=P(AB)P(B)+P(AC)P(C)=61313+51323=1639.P(A) = P(A \cap B) + P(A \cap C) = P(A|B)P(B) + P(A|C)P(C) = \frac{6}{13} \cdot \frac{1}{3} + \frac{5}{13} \cdot \frac{2}{3} = \frac{16}{39}.


Answer.

16/39

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