A rail company knows that on average they will have 3 people ill each day. In order to make plans for replacements they have asked you to calculate the following probabilities: In a single day - (1) No employees ill (2)Two or less employees ill (3) Four or more employees ill
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Expert's answer
2011-08-11T09:21:28-0400
The unknown probabilities depend on distribution of number of number of ill patients. But in such situations the most frequently is used Poisson distribution. 1) No employees ill, X = 0, lambda=3 P(0) = e-3 30/0! = 0.5*1/1 = .05
2)Two or less ill P(X<=2) = P(0) + P(1) + P(2) = .15
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