Question #38571

A random sample of n=100 will be selected from this population and ^P proportion of couples that are mixed what are the mean and standard deviation of the sampling mean of ^P? 7% of the united states married that are mixed.
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Expert's answer

2014-01-24T13:17:28-0500

Answer on Question # 38571 – Math – Statistics and Probability

A random sample of n=100n=100 will be selected from this population and ^P proportion of couples that are mixed what are the mean and standard deviation of the sampling mean of ^P? 7% of the united states married that are mixed.

Solution

The sample proportion p^=Xn\hat{p} = \frac{X}{n} is a reasonable estimator of the population proportion pp, where XX is the count of the number of sampled elements possessing the characteristic. The properties of expectation give

the mean


E(p^)=p=0.07;E(\hat{p}) = p = 0.07;


the standard deviation


sd(p^)=pq/n=0.07×0.93/1000.026.sd(\hat{p}) = \sqrt{pq/n} = \sqrt{0.07 \times 0.93/100} \approx 0.026.


The properties of the sample mean Xˉ=X1+X2++Xnn\bar{X} = \frac{X_1 + X_2 + \cdots + X_n}{n} as an estimator of the population mean μ\mu, if X1,X2,,XnX_1, X_2, \ldots, X_n is a random sample:


E(Xˉ)=μE(\bar{X}) = \musd(Xˉ)=σnsd(\bar{X}) = \frac{\sigma}{\sqrt{n}}

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