Question

In a multi-user operating system, 20 requests are made to use a particular resource per hour on an average. The probability that no requests are made in 45 minutes is

a) e^(-15)
b) e^(-5)
c) 1-e^(-5)
d) 1-e^(-10)

Answer 1

Answer on Question 37838, Math, Statistics and Probability

20 requests per hour in average is the same that there are 15 request in 45 min or 1 every 3 minutes. so, probability, that there will be no request in any three minutes is

$e^{-1}$

Hence, if have 15 times of 3 minutes, the probability of have no request is

$e^{-15}$

answer is a) $e^{-15}$.