Scores of an achievement test show that it follows a normal distribution. Its mean is 79 with a
standard deviation of 8. Find the probability that students’ scores will be higher than the passing score
of 70.
We have a normal distribution, "\\mu=79, \\sigma=8."
Let's convert it to the standard normal distribution,
"z=\\cfrac{x-\\mu}{\\sigma}=\\cfrac{70-79}{8}=-1.13;"
"P(X>70)=P(Z>-1.13)=1-P(Z<-1.13)=\\\\\n=1-0.1292=0.8708\\ \\text{\u200b(from z-table).}"
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