The weights(kg) of 11 stem B follow a normal distribution and has a mean of 50 and a standard deviation of 5 how many students have weights greater than 57?
We have a normal distribution with "\\mu=50," "\\sigma=5."
Let's find the corresponding z-score for "X=57" :
"z=\\frac{X-\\mu}{\\sigma}=\\frac{57-50}{5}=1.4"
So,
"P(X>57)=P(z>1.4)=1-P(z<1.4)=1-0.9192=0.0808."
As the total number of students is 11 and the probability to have weight greater than 57 is 0.0808,
the number of students of such weight equals:
"11\\cdot 0.0808=0.8888\\approx1."
Answer: The number of students that have weights greater than 57 is "\\approx1."
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