Question #349582

A quality control want to estimate the proportion of high quality goods out of a batch of products with a 90% confidence level and a margin of error of 5%. How may products must he tes

1
Expert's answer
2022-06-10T14:22:29-0400

A 90% confidence interval has a z-score (a critical value) zc=1.6449.z_c=1.6449.



ME=zc×p(1p)nME=z_c\times\sqrt{\dfrac{p(1-p)}{n}}=1.6449×0.5(10.5)n=0.05=1.6449\times\sqrt{\dfrac{0.5(1-0.5)}{n}}=0.05n=(16.449)2n=(16.449)^2n=271n=271

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