We have population values 1,2,3,4,5,6,7,8, population size N=8 and sample size n=3.
Mean of population (μ) = 81+2+3+4+5+6+7+8=4.5
b.Variance of population
σ2=nΣ(xi−xˉ)2=81(12.25+6.25+2.25+0.25+0.25+2.25+6.25+12.25)=5.25
σ=σ2=5.25≈2.29
Select a random sample of size 2 without replacement. We have a sample distribution of sample mean.
The number of possible samples which can be drawn without replacement is NCn=8C3=56.
no1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556Sample1,2,31,2,41,2,51,2,61,2,71,2,81,3,41,3,51,3,61,3,71,3,81,4,51,4,61,4,71,4,81,5,61,5,71,5,81,6,71,6,81,7,82,3,42,3,52,3,62,3,72,3,82,4,52,4,62,4,72,4,82,5,62,5,72,5,82,6,72,6,82,7,83,4,53,4,63,4,73,4,83,5,63,5,73,5,83,6,73,6,83,7,84,5,64,5,74,5,84,6,74,6,84,7,85,6,75,6,85,7,86,7,8Samplemean (xˉ)6/37/38/39/310/311/38/39/310/311/312/310/311/312/313/312/313/314/314/315/316/39/310/311/312/313/311/312/313/314/313/314/315/315/316/317/312/313/314/315/314/315/316/316/317/318/315/316/317/317/318/319/318/319/320/321/3
Xˉ6/37/38/39/310/311/312/313/314/315/316/317/318/319/320/321/3f(Xˉ)1/561/562/563/564/565/566/566/566/566/565/564/563/562/561/561/56
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