Question #349493

Samples of three cards are drawn at random

from a population of eight cards numbered

from 1 to 8.


  1. Construct a histogram of the sampling

distribution of the means.


1
Expert's answer
2022-06-10T13:51:12-0400

We have population values 1,2,3,4,5,6,7,8, population size N=8 and sample size n=3.

Mean of population (μ)(\mu) = 1+2+3+4+5+6+7+88=4.5\dfrac{1+2+3+4+5+6+7+8}{8}=4.5

b.Variance of population 


σ2=Σ(xixˉ)2n=18(12.25+6.25+2.25+0.25\sigma^2=\dfrac{\Sigma(x_i-\bar{x})^2}{n}=\dfrac{1}{8}(12.25+6.25+2.25+0.25+0.25+2.25+6.25+12.25)=5.25+0.25+2.25+6.25+12.25)=5.25


σ=σ2=5.252.29\sigma=\sqrt{\sigma^2}=\sqrt{5.25}\approx2.29


Select a random sample of size 2 without replacement. We have a sample distribution of sample mean.

The number of possible samples which can be drawn without replacement is NCn=8C3=56.^{N}C_n=^{8}C_3=56.

noSampleSamplemean (xˉ)11,2,36/321,2,47/331,2,58/341,2,69/351,2,710/361,2,811/371,3,48/381,3,59/391,3,610/3101,3,711/3111,3,812/3121,4,510/3131,4,611/3141,4,712/3151,4,813/3161,5,612/3171,5,713/3181,5,814/3191,6,714/3201,6,815/3211,7,816/3222,3,49/3232,3,510/3242,3,611/3252,3,712/3262,3,813/3272,4,511/3282,4,612/3292,4,713/3302,4,814/3312,5,613/3322,5,714/3332,5,815/3342,6,715/3352,6,816/3362,7,817/3373,4,512/3383,4,613/3393,4,714/3403,4,815/3413,5,614/3423,5,715/3433,5,816/3443,6,716/3453,6,817/3463,7,818/3474,5,615/3484,5,716/3494,5,817/3504,6,717/3514,6,818/3524,7,819/3535,6,718/3545,6,819/3555,7,820/3566,7,821/3\def\arraystretch{1.5} \begin{array}{c:c:c:c:c} no & Sample & Sample \\ & & mean\ (\bar{x}) \\ \hline 1 & 1,2,3 & 6/3 \\ \hdashline 2 & 1,2,4 & 7/3 \\ \hdashline 3 & 1,2,5 & 8/3 \\ \hdashline 4 & 1,2,6 & 9/3 \\ \hdashline 5 & 1,2,7 & 10/3 \\ \hdashline 6 & 1,2,8 & 11/3 \\ \hdashline 7 & 1,3,4 & 8/3 \\ \hdashline 8 & 1,3,5 & 9/3 \\ \hdashline 9 & 1,3,6& 10/3 \\ \hdashline 10 & 1,3,7 & 11/3 \\ \hdashline 11 & 1,3,8 & 12/3 \\ \hdashline 12 & 1,4,5 & 10/3 \\ \hdashline 13 & 1,4,6 & 11/3 \\ \hdashline 14 & 1,4,7 & 12/3 \\ \hdashline 15 & 1,4,8 & 13/3 \\ \hdashline 16 & 1,5,6 & 12/3 \\ \hdashline 17 & 1,5,7 & 13/3 \\ \hdashline 18 & 1,5,8 & 14/3 \\ \hdashline 19 & 1,6,7 & 14/3 \\ \hdashline 20 & 1,6,8 & 15/3 \\ \hdashline 21 & 1,7,8 & 16/3 \\ \hdashline 22 & 2,3,4 & 9/3 \\ \hdashline 23 & 2,3,5 & 10/3 \\ \hdashline 24 & 2,3,6 & 11/3 \\ \hdashline 25 & 2,3,7 & 12/3 \\ \hdashline 26 & 2,3,8 & 13/3 \\ \hdashline 27 & 2,4,5 & 11/3 \\ \hdashline 28 & 2,4,6 & 12/3 \\ \hdashline 29 & 2,4,7 & 13/3 \\ \hdashline 30 & 2,4,8 & 14/3 \\ \hdashline 31 & 2,5,6 & 13/3 \\ \hdashline 32 & 2,5,7 & 14/3 \\ \hdashline 33 & 2,5,8 & 15/3 \\ \hdashline 34 & 2,6,7 & 15/3 \\ \hdashline 35 & 2,6,8 & 16/3 \\ \hdashline 36 & 2,7,8 & 17/3 \\ \hdashline 37 & 3,4,5 & 12/3 \\ \hdashline 38 & 3,4,6 & 13/3 \\ \hdashline 39 & 3,4,7 & 14/3 \\ \hdashline 40 & 3,4,8 & 15/3 \\ \hdashline 41 & 3,5,6 & 14/3 \\ \hdashline 42 & 3,5,7 & 15/3 \\ \hdashline 43 & 3,5,8 & 16/3 \\ \hdashline 44 & 3,6,7 & 16/3 \\ \hdashline 45 & 3,6,8 & 17/3 \\ \hdashline 46 & 3,7,8 & 18/3 \\ \hdashline 47 & 4,5,6 & 15/3 \\ \hdashline 48 & 4,5,7 & 16/3 \\ \hdashline 49 & 4,5,8 & 17/3 \\ \hdashline 50 & 4,6,7& 17/3 \\ \hdashline 51 & 4,6,8 & 18/3 \\ \hdashline 52 & 4,7,8 & 19/3 \\ \hdashline 53 & 5,6,7 & 18/3 \\ \hdashline 54 & 5,6,8 & 19/3 \\ \hdashline 55 & 5,7,8 & 20/3 \\ \hdashline 56 & 6,7,8 & 21/3 \\ \hdashline \end{array}





Xˉf(Xˉ)6/31/567/31/568/32/569/33/5610/34/5611/35/5612/36/5613/36/5614/36/5615/36/5616/35/5617/34/5618/33/5619/32/5620/31/5621/31/56\def\arraystretch{1.5} \begin{array}{c:c:} \bar{X} & f(\bar{X}) \\ \hline 6/3 & 1/56 \\ \hdashline 7/3 & 1/56 \\ \hdashline 8/3 & 2/56 \\ \hdashline 9/3 & 3/56 \\ \hdashline 10/3 & 4/56 \\ \hdashline 11/3 & 5/56 \\ \hdashline 12/3 & 6/56 \\ \hdashline 13/3 & 6/56 \\ \hdashline 14/3 & 6/56 \\ \hdashline 15/3 & 6/56 \\ \hdashline 16/3 & 5/56 \\ \hdashline 17/3 & 4/56 \\ \hdashline 18/3 & 3/56 \\ \hdashline 19/3 & 2/56 \\ \hdashline 20/3 & 1/56 \\ \hdashline 21/3 & 1/56 \\ \hdashline \end{array}





Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS