Find the 99th. Percentile of the t-distribution with 18 degrees of freedom?
P(T<t)=0.99→t=2.55.P(T<t)=0.99\to t=2.55.P(T<t)=0.99→t=2.55.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment