Answer to Question #348212 in Statistics and Probability for Micay

Question

. An employee’s weekly income in a certain online job follows a normal distribution with a mean of PHP1,000 and a standard deviation of PHP100. What is the z value for the income of:

Answer 1

a)

$$z=\dfrac{x-\mu}{\sigma}=\dfrac{1100-1000}{100}=1$$

b)

$$z=\dfrac{x-\mu}{\sigma}=\dfrac{900-1000}{100}=-1$$