Answer to Question #347594 in Statistics and Probability for Hera

Question

Suppose in a dice game, the person who rolls two dice wins if his rolls results in a pair of numbers whose sum is 7 or 11. in how many ways can he or she win?

Answer 1

$$\def\arraystretch{1.5} \begin{array}{c:c:c:c:c:c:c} & 1 & 2 & 3 & 4 & 5 & 6\\ \hdashline 1& 2 & 3 & 4 & 5 & 6 & 7\\ \hdashline 2 & 3 & 4 & 5 & 6 & 7 & 8\\ \hdashline 3 & 4 & 5 & 6 & 7 & 8 & 9\\ \hdashline 4 & 5 & 6 & 7 & 8 & 9 & 10\\ \hdashline 5 & 6 & 7 & 8 & 9 & 10 & 11\\ \hdashline 6 & 7 & 8 & 9 & 10 & 11 & 12\\ \hdashline \end{array}$$

$$6+2=8$$

He or she can win in 8 ways.