Question #347214

2. Changes in airport procedures require considerable planning. Arrival rates of aircraft are important factors that must be taken into account. Suppose small aircraft arrive at a certain airport, according to a Poisson process, at the rate of 5 per hour. Thus, the Poisson parameter for arrivals over a period of hours is μ = 5t.

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

(b) What is the probability that at least 4 arrive during a 1-hour period?

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?


1
Expert's answer
2022-06-02T18:21:57-0400

a)


P(X=4)=e5(5)44!=0.175467P(X=4)=\dfrac{e^{-5}(5)^4}{4!}=0.175467

b)


P(X4)=1P(X=0)P(X=1)P(X\ge4)=1-P(X=0)-P(X=1)

P(X=2)P(X=3)-P(X=2)-P(X=3)

=1e5(5)00!e5(5)11!=1-\dfrac{e^{-5}(5)^0}{0!}-\dfrac{e^{-5}(5)^1}{1!}

e5(5)22!e5(5)33!=0.734974-\dfrac{e^{-5}(5)^2}{2!}-\dfrac{e^{-5}(5)^3}{3!}=0.734974

c)


λt=5(12)=60\lambda t=5(12)=60


The Poisson distribution can be approximated with Normal when λ is large

μ=λt=60,σ2=λt=60\mu=\lambda t=60, \sigma^2=\lambda t=60


P(X75)P(X>74.5)P(X\ge75)\approx P(X>74.5)

=1P(Z74.56060)=1-P(Z\le\dfrac{74.5-60}{\sqrt{60}})

=1P(Z1.871942)0.0306=1-P(Z\le1.871942)\approx0.0306


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