Question #346994

Question 1.2 [2, 2, 2]


Suppose that we have two events A and B such that P A( ) 0.8 = and P B( ) 0.7 = .


a) Is it possible that PA B ( ) 0.1 ∩ = ? Explain your answer.


b) What is the smallest possible value of PA B ( ) ∩ ?


c) What is the largest possible value of PA B ( ) ∩ ?

1
Expert's answer
2022-06-07T12:20:36-0400
P(AB)=P(A)+P(B)P(AB)P(A\cup B)=P(A)+P(B)-P(A\cap B)

P(AB)=P(A)+P(B)P(AB)P(A\cap B)=P(A)+P(B)-P(A\cup B)

Since P(A)=0.8,P(B)=0.7,0P(AB)1,P(A)=0.8, P(B)=0.7,0\le P(A\cup B)\le1,

P(AB)min(P(A),P(B))P(A\cap B)\le \min{(P(A), P(B))} then


P(AB)=P(A)+P(B)P(AB)P(A\cup B)=P(A)+P(B)-P(A\cap B)


0P(A)+P(B)P(AB)10\le P(A)+P(B)-P(A\cap B)\le 1

00.8+0.7P(AB)10\le 0.8+0.7-P(A\cup B)\le 1

P(AB)P(B),P(AB)08+0.71P(A\cap B)\le P(B), P(A\cap B)\ge 08+0.7-1


0.5P(AB)0.70.5\le P(A\cap B)\le 0.7

a) It is impossible that P(AB)=0.1.P(A\cap B)=0.1.


b) The smallest possible value of P(AB)P(A\cap B) is 0.5.0.5.


c) The largest possible value of P(AB)P(A\cap B) is 0.7.0.7.


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