(Distribution Probability)
1.
Probability of the prize P5,000.00:
"p_1=\\frac{1}{1000}\\cdot\\frac{3}{5}=\\frac{3}{5000}"
Probability of the prize P10,000.00:
"p_2=\\frac{1}{1000}\\cdot\\frac{1}{5}=\\frac{1}{5000}"
Probability of the prize P20,000.00:
"p_3=\\frac{1}{1000}\\cdot\\frac{1}{5}=\\frac{1}{5000}"
The expected value of a ticket:
"E(X)=100\\cdot0.999+(100-5000)\\cdot3\/5000+(100-10000)\\cdot1\/5000"
"+(100-20000)\\cdot1\/5000=99.9-\\frac{44500}{5000}=99.9-8.9=P\\ 91"
2.
Let's say I get X as a bonus.
Then X=0, 100, 500, 1000
There are 52 cards.
P(X=500)=12/52
P(X=1000)= 4/52
P(X=100)=26/52-2/52-6/52 = 18/52 [Exclude events that exists in other possibilities]
P(X=0)=1-12/52-4/52-18/52=18/52
So, the expected value that you can possibly win
E= 0*18/52 + 100*18/52 + 500*12/52 + 1000*4/52=157.7
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