Question #345616

‘Bhartdarshan’ is an Internet-based travel agency wherein customers can see videos of the

cities they plan to visit. The number of hits daily is a normally distributed random variable

with a mean of 10,000 and a standard deviation of 2,400.

a. What is the probability of getting more than 12,000 hits?

b. What is the probability of getting fewer than 9,000 hits?


Expert's answer

a.

P(X>12000)=1−P(Z≤12000−100002400)P(X>12000)=1-P(Z\le\dfrac{12000-10000}{2400})

≈1−P(Z≤0.8333)≈0.2023\approx1-P(Z\le 0.8333)\approx0.2023

b.

P(X<9000)=P(Z<9000−100002400)P(X<9000)=P(Z<\dfrac{9000-10000}{2400})

≈P(Z≤−0.4167)≈0.3385\approx P(Z\le -0.4167)\approx0.3385


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