Answer to Question #345616 in Statistics and Probability for add

Question

‘Bhartdarshan’ is an Internet-based travel agency wherein customers can see videos of the

cities they plan to visit. The number of hits daily is a normally distributed random variable

with a mean of 10,000 and a standard deviation of 2,400.

a. What is the probability of getting more than 12,000 hits?

b. What is the probability of getting fewer than 9,000 hits?

Answer 1

a.

$$P(X>12000)=1-P(Z\le\dfrac{12000-10000}{2400})$$

$$\approx1-P(Z\le 0.8333)\approx0.2023$$

b.

$$P(X<9000)=P(Z<\dfrac{9000-10000}{2400})$$

$$\approx P(Z\le -0.4167)\approx0.3385$$