Answer to Question #345407 in Statistics and Probability for Tiobong

Question

In a company having 80 employees, 60 earn 10.00 per hour and 20 earn $13.00 per hour. Determine the mean earning per hour.b would the answer in part (a) be the same if the 60 employees earn a mean hourly wage.

Answer 1

a)

$mean=\dfrac{n_1x+n_2y}{n_1+n_2}=\dfrac{60(10)+20(13)}{60+20}=10.75$

b)

If $n_1$ employees earn a mean hourly wage $\bar{x}$ then their total amount earned is $n_1\bar{x}.$

If $n_2$ employees earn $y$ per hour then their total amount earned is $n_2y.$

Then

$mean=\dfrac{n_1\bar{x}+n_2y}{n_1+n_2}=\dfrac{60(10)+20(13)}{60+20}=10.75$

The answer would be the same.