Question #345181

The leader of the Factory Worker claims that the average pay of factory workers in



Marikina City is less than 500 php. A random sample of 16 factory workers was



interviewed and resulted on the average of 350 php. Using a significance level of



0.05 and standard deviation of 92. Determine if there is sufficient evidence that the



claim is true.

1
Expert's answer
2022-05-27T11:40:06-0400

The following null and alternative hypotheses need to be tested:

H0:μ500H_0:\mu\ge500

H1:μ<500H_1:\mu<500

This corresponds to a left-tailed test, for which a z-test for one mean, with known population standard deviation will be used.

Based on the information provided, the significance level is α=0.05,\alpha = 0.05, and the critical value for a left-tailed test is zc=1.6449.z_c = -1.6449.

The rejection region for this left-tailed test is R={z<1.6449}.R = \{z<-1.6449\}.

The z-statistic is computed as follows:


z=xˉμσ/n=35050092/166.5217z=\dfrac{\bar{x}-\mu}{\sigma/\sqrt{n}}=\dfrac{350-500}{92/\sqrt{16}}\approx-6.5217

Since it is observed that z=6.5217<1.6449=zc,z=-6.5217<-1.6449=z_c, it is then concluded that the null hypothesis is rejected.

Using the P-value approach:

The p-value is p=P(z<6.5217)=0,p=P(z<-6.5217)=0, and since p=0<0.05=α,p= 0<0.05=\alpha, it is concluded that the null hypothesis is rejected.

Therefore, there is enough evidence to claim that the population mean μ\mu

is less than 500, at the α=0.05\alpha = 0.05 significance level.


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